Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
Solution given:
model A printers [a] prints=80books per day
model B printers [b] prints=55books per day
total no of printers =9
no of model A printers be x
and
no of model B printers be [9-x]
According to the question;
ax+(9-x)b=670 books
substituting value of a and b; we get
80x+(9-x)55=670
80x-55x+495=670
25x=670-495=175
x=
=7
So;
no of model A printers =x=<u>7</u>
no of model B printers =9-x=9-7=<u>2</u>
<u>is</u><u> </u><u>your</u><u> </u><u>answer</u><u>.</u>
Answer:
Z = 6
Step-by-step explanation:
Z/12 = Cos(60°)
Z/12 = 1/2
So uhh I’m so sorry to tell you but I don’t know how to do math myself and I just need points so I’m answering this.. but I’m sure If you just cheat off a smart person in your class you’ll be fine. If you need any tips on how to cheat lmk I’ll gladly help
1.468*3.14 is around 4.6 so B)
And 65.97/4.6 is about 14.3 so C)