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Len [333]
3 years ago
7

A school paid $31.25 for each calculator. If the school spent $500 on calculators, how many did the school buy?

Mathematics
2 answers:
Katen [24]3 years ago
8 0

Answer:

Divide 500 by 31.25$ which equals to 16

Sedbober [7]3 years ago
5 0

Answer:

A school paid $31.25 for each calculator.

If the school spent $500 on calculators, the number of purchased calculators:

N = 500/31.25 = 16

Hope this helps!

:)

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The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

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What is the total amount of sap the trees produced that day ?
Vikki [24]

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Step-by-step explanation:

hope this helps

6 0
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The equation y = 0.035x shows the relationship between the grams and ounces.
scoundrel [369]
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The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,
ivanzaharov [21]

Answer:

  CD = 14 cm; DE = 21 cm

Step-by-step explanation:

The perimeter is the sum of side lengths (in centimeters), so ...

  CD + DE + CF + EF = 55

  CD + DE + 8 + 12 = 55 . . . . . . . substittute for CF and EF

  CD + DE = 35 . . . . . . . . . . . . . . subtract 20

___

The segment DF is a diagonal of the rhombus, so bisects angle D. That angle bisector divides ΔCDE into segments that are proportional. That is, ...

  CD/DE = CF/EF = 8/12 = 2/3

___

So, we have two segments whose sum is 35 (cm) and whose ratio is 2 : 3. The total of "ratio units is 2+3=5, so each must stand for a length unit of 35/5 = 7 (cm). The sides are ...

  CD = 2·7 cm = 14 cm

  DE = 3·7 cm = 21 cm

<em>Check</em>

  CD + DE = (14 +21) cm = 35 cm . . . . . matches requirements

7 0
3 years ago
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