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xz_007 [3.2K]
2 years ago
11

The population of a certain species of fish in a lake after t years is given by P(t)=18801 + 1.42e-0.037t. Find the horizontal a

symptote. What does it represent in this situation?

Mathematics
1 answer:
Lunna [17]2 years ago
4 0

Answer:

a) 188 fishes

b) 1259 fishes

Hope this helps!

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Through (4,-4) ; perpendicular to 6y=x-12
BARSIC [14]

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

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So the equation for the perpendicular line is y = -6x + 20

3 0
3 years ago
One ticket costs $15.45. Three tickets would cost?
Troyanec [42]
46.35 is the answer
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2 years ago
Slope=-3 goes through (1,2) whats the equation
dedylja [7]

Hi student, let me help you out! :)

..............................................................................................................................................

We are asked to find the equation of the line, using the given information:

\star~\mathrm{-3}, which is the slope

\star~\mathrm{(1,2)} which is a point that the line contains

\triangle~\fbox{\bf{KEY:}}

  • The slope is the number before x, in the form \mathtt{y=mx+b}.

Since "m" is the slope, and we're given what the slope is, we can substitute -3 for m:

\dag~\mathtt{y=-3x+b}

|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||

Now, we need to find the y intercept, "b", of the line.

Here's how it's done:

Remember the point that the line contains, (1,2)?

Well, its y-coordinate is 2; so what we do is substitute 2 for y:

\dag~\mathtt{2=-3x+b}

Also, its x-coordinate is 1, so we substitute 1 for x:

\dag~\mathtt{2=-3(1)+b}

Now, solve for b:

\dag~\mathtt{2=-3+b}

Add 3 to both sides:

\dag~\mathtt{2+3=b}

Thus, we have

\dag~\mathtt{5=b}

Thus, the equation of the line is:

\bigstar\underline{\boxed{\mathtt{y=-3x+5}}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

\overline{\underline{~~~~~~~~~~~~~~~~~~~~~~~~~~}}

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What value of p will make the expression below a perfect square? x^2 - x + P
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Answer:

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Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² - x, that is

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x² - x = (x - \frac{1}{2} )² + \frac{1}4}

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