The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

3 0

3 years ago

Read 2 more answers

Sophie borrowed $2000 and took 3 years to repay the loan and $900 interest.

dedylja [7]

I = p * r * n

i is the interest
p is the principal
r is the interest rate per time period
n is the number of time periods.

in your problem:

i = 900
p = 2000
r = what you want to find
n = 3 years

formula becomes 900 = 2000 * r * 3

solve for r to get r = 900 / 2000 / 3 = .15

that's .15 interest rate per year = 15% per year.

at a nominal interest rate of .15 per year, the interest rate per month would be .15/12 = .0125 per month.

the remaining balance at the end of 6 month is equal to 1907.140183

7 0

2 years ago

Simplify the expression below

Brilliant_brown [7]

Answer:

− 4 x + 20

Step-by-step explanation:

3 0

2 years ago