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zaharov [31]
3 years ago
10

Find the missing side. Round to the nearest tenth. A.7.1B.5.1C.5.1 D.6.1​

Mathematics
2 answers:
Stels [109]3 years ago
7 0

Answer:

5,1

Step-by-step explanation:

x= tan27⁰ x 10 ≈ 5,1

.....

e-lub [12.9K]3 years ago
6 0

Answer:

b or c or 5.1

Step-by-step explanation:

The basic trig identity that does not involve the hypotenuse is the Tan(theta).

Tan(theta) = opposite / adjacent. That definition applies only to a right triangle. It has to be modified if the triangle is some other kind.

The opposite side is the one not making up the reference angle (x in this case).

The adjacent side is the one making up the angle that is not the hypotenuse.

opposite side = x

adjacent side = 10

theta = 27 degrees.

Tan(theta) = opposite / adjacent

Tan(27) = x / 10

Tan(27) = 0.5095

0.5095 = x / 10               Multiply by 10

10*0.5095 = x

x = 5.095

It rounds to 5.1

No one except the answer key can know whether to choose b or c.

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4 0
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Read 2 more answers
Please no "files": Simplify. Express your answer as the given base raised to a single exponent.
Kipish [7]

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Step-by-step explanation:

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5 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
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