The squares here are organized in a way where one can prove the Pythagorean theorem. The Pythagorean theorem is the theorem that states that the length of one side of a right triangle, squared, plus the length of another leg of the triangle, squared, is equal to the hypotenuse squared. This is a² + b² = c². Since the areas of the squares are the squared lengths of the sides, that means that D. is the right answer.
Answer:
No; the slopes of segment EF and segment DF are not opposite reciprocals.
Step-by-step explanation:
The slope between two points O(e, f) and X (g,h) is given as:

The slopes of segment EF and segment DF are given below:

For triangle DEF to be a right triangle, DF and EF are supposed to be perpendicular to each other. Two line are said to be perpendicular if the product of their slope is -1, i.e the slope of one line is the negative reciprocal (opposite reciprocal) of the other line.
Since the slope of DF and EF are not opposite reciprocals, ΔDEF is not a right triangle.
Answer:
Number 4 is neither, number 6 is perpendicular
Step-by-step explanation:
The answer is x > 4.5.
Explanation:
-24 > -6(x - 0.5)
-24 > -6x + 3
6x > 3 + 24
6x > 27
x > 27/6
x > 4.5
Hope this helps :)
Answer:
We want to construct a confidence interval at 99% of confidence, so then the significance level would be
and the value of
. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:

And we can use the following excel code:
"=NORM.INV(0.005,0,1)"
Step-by-step explanation:
For this case we have the following info given:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be
and the value of
. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:

And we can use the following excel code:
"=NORM.INV(0.005,0,1)"