Answer:
<em>1 ) m∠ 1 = 72°, m∠2 = 108°,</em>
<em>2 ) m∠ 1 = 22.5°, m∠2 = 67.5°</em>
Step-by-step explanation:
Question 2 ) Assuming these are supplementary angles, we know that their measures form a linear pair that add to 180°;
let us assign these angles as 1, and 2 ⇒ m∠ 1 + m∠ 2 = 180,
with the given ratios 2 to 3, we can say x ⇒ one part of measure, so that ⇒ 2x + 3x = 180,
2x + 3x = 180 ⇒ combine like terms,
5x = 180 ⇒ divide either side by 5,
x = 36°
If this is so, m∠ 1 = 2x = 2 * ( 36 ) = 72°, and m∠ 2 = 3x = 3 * ( 36 ) = 108°;
<em>Solution; m∠ 1 = 72°, m∠2 = 108°</em>
Question 3 ) If it is known that two angles are complementary to one another, we can say their measures add to 90°;
let us one more, assign these angles as 1 and 2 ⇒ m∠ 1 + m∠ 2 = 180,
knowing that the measure of one angle is 3 times that of the other angle we can derive the ratio 1 : 3 in the manner smaller ∠ measure : bigger ∠ measure so that ⇒ x + 3x = 90,
x + 3x = 90 ⇒ combine like terms,
4x = 90 ⇒ divide either side by 4,
x = 22.5
If this is so, m∠ 1 = x = 1 * ( 22.5 ) = 22.5°, and m∠ 2 = 3x = 3 * ( 22.5 ) = 67.5°;
<em>Solution; m∠ 1 = 22.5°, m∠2 = 67.5°</em>
