Question

Question 2

Answer 1

Answer:

1 ) m∠ 1 = 72°, m∠2 = 108°,

2 ) m∠ 1 = 22.5°, m∠2 = 67.5°

Step-by-step explanation:

Question 2 ) Assuming these are supplementary angles, we know that their measures form a linear pair that add to 180°;

let us assign these angles as 1, and 2 ⇒ m∠ 1 + m∠ 2 = 180,

with the given ratios 2 to 3, we can say x ⇒ one part of measure, so that ⇒ 2x + 3x = 180,

2x + 3x = 180 ⇒ combine like terms,

5x = 180 ⇒ divide either side by 5,

x = 36°

If this is so, m∠ 1 = 2x = 2 * ( 36 ) = 72°, and m∠ 2 = 3x = 3 * ( 36 ) = 108°;

Solution; m∠ 1 = 72°, m∠2 = 108°

Question 3 ) If it is known that two angles are complementary to one another, we can say their measures add to 90°;

let us one more, assign these angles as 1 and 2 ⇒ m∠ 1 + m∠ 2 = 180,

knowing that the measure of one angle is 3 times that of the other angle we can derive the ratio 1 : 3 in the manner smaller ∠ measure : bigger ∠ measure so that ⇒ x + 3x = 90,

x + 3x = 90 ⇒ combine like terms,

4x = 90 ⇒ divide either side by 4,

x = 22.5

If this is so, m∠ 1 = x = 1 * ( 22.5 ) = 22.5°, and m∠ 2 = 3x = 3 * ( 22.5 ) = 67.5°;

Solution; m∠ 1 = 22.5°, m∠2 = 67.5°