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Blizzard [7]
3 years ago
7

Jim types 1800 words in 25 minutes. How many words does he type per minute

Mathematics
1 answer:
kirill [66]3 years ago
3 0
1800 divided by 25 is 72. He types 72 words per minute.
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Find the equation of the line perpendicular to y=−2 that passes through the point (4, −2).
lawyer [7]

x = 4

because it is perpendicular, the new equation has to be a vertical since the original was horizontal. We know that it passes through (4,-2) so it has to be x=4

4 0
3 years ago
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What is the greatest three-digit multiple of 33 that can be written using three different digits?
tatuchka [14]

Answer:

I don't if this is right but is the 629

Step-by-step explanation:

8 0
3 years ago
If f(x)= 3/x+2- square root x-3, complete the following statement: f(19)=
I am Lyosha [343]

f(7)≈1.6666                Please mark me as brainliest

round

f(7)=1.67

The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.

8 0
3 years ago
Please tell me the function( will mark as brainiest) thanks
Alecsey [184]

Answer:

y = 8x+8

Step-by-step explanation:

We can solve for the function by finding the slope of the linear function using two points. Let's use (0,8) and (1,16)

Slope formula is: m = \frac{y2-y1}{x2-x1}

Plug in the 2 points: m = \frac{16-8}{1-0}

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So now, for the equation y = mx+b, we have m which is y = 8x+b

Now we need to find b by using another point from this linear function.

We can use the point (2,24).

Plug this point into the equation y = 8x+b

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We have now found the equation of the linear function: y = 8x+8

6 0
3 years ago
Simplify. Please show work
GuDViN [60]

Answer:

\frac{4b^5}{c^3}

Step-by-step explanation:

\frac{36b^4c^2}{9b^{-1}c^5}

\frac{36b^4c^2}{9b^{-1}c^5}\\\\\frac{4b^{4+1}}{c^{5-2}}\\\\\frac{4b^5}{c^3}

Hope this helps!

5 0
2 years ago
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