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Maslowich
3 years ago
14

Solve sqrt 3-5x= sqrt x+2 what is the value of x

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

x=\frac{1}{6}

Step-by-step explanation:

\sqrt{3-5x}=\sqrt{x+2}\\Square\:both\:sides\\\left(\sqrt{3-5x}\right)^2=\left(\sqrt{x+2}\right)^2\\\mathrm{Expand\:}\left(\sqrt{3-5x}\right)^2:\quad 3-5x\\\mathrm{Expand\:}\left(\sqrt{x+2}\right)^2:\quad x+2\\3-5x=x+2\\\mathrm{Solve\:}\:3-5x=x+2:\quad x=\frac{1}{6}\\x=\frac{1}{6}\\\mathrm{Verify\:Solutions}:\quad x=\frac{1}{6}\space\mathrm{True}\\\mathrm{The\:solution\:is}\\x=\frac{1}{6}

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

To find the intersection of two lines, we want to find the value when they equal each other. To do this, we want to set the equations equal to each other.

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Now let's set the equations equal to each other. Since they both equal y, we can set the opposite sides equal to each other.

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Now we want to find y by plugging x = 0 back into the equations.

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