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2 years ago

Solve.

Mathematics

1 answer:

Tpy6a [65]2 years ago

4 0

Answer:

1. x > 13

2. x < -2

3. x < 5

Step-by-step explanation:

2x - 3 > 23

→Add 3 to both sides:

2x > 26

→Divide both sides by 2:

x > 13

2x - 3 > 3x - 1

→Subtract 2x from both sides:

-3 > x - 1

→Add 1 to both sides:

-2 > x

5x - 4 < 21

→Add 4 to both sides:

5x < 25

→Divide both sides by 5:

x < 5

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Geometry HW! PLS HELP

BlackZzzverrR [31]

The answer is B. CD=KL, DE=LM, EF=MN, and so on

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3 years ago

Question 3

Elan Coil [88]

Answer:

Domain: $-3\leq x\leq 1$

Range: $-4\leq y\leq 0$

Step-by-step explanation:

If you find the coordinate of the graph you can get the domain and range

(-3,0), (-2,-4), (-1,-2), (0,0), (1, -4)

Now that we have that find the domain and range

Domain - x coordinate

Range - y coordinate

Domain: (-3, -2, -1, 0, 1)

Range: (-4, -2, 0)

Since the domain ranges from -3 to 1 you can use the inequality $-3\leq x\leq 1$ to represent the domain and $-4\leq y\leq 0$ for the range

7 0

3 years ago

The sum of three consecutive odd integers is 57. what are the three integers

asambeis [7]

Answer:

17,19,21

Step-by-step explanation:

let the first odd number be "x"

formular : (x)+(x+2)+(x+4).

3x+6=57

3x=57-6

3x=51

x=51/3

x=17

apply the formular.

17,(17+2),(17+4)

17,19,21.

6 0

3 years ago

Please help me I’m struggling :’(

Vesna [10]

Answer:

B. $x = \sqrt{40}$

Step-by-step explanation:

Using Pythagorean theorem, find the value of x.

Pythagorean theorem is given as $c^2 = a^2 + b^2$

Where,

c is the longest side of a right angled ∆ = the hypotenuse = x

a and b are legs of the right angled ∆ = 2 and 6

Plug in the values into the equation and solve for x

$x^2 = 2^2 + 6^2$

$x^2 = 4 + 36$

$x^2 = 40$

$x = \sqrt{40}$

5 0

3 years ago

Can someone pls help with this

Eddi Din [679]

:
You put 57 in F (on the left side)
You put 49 in S ( on the right side)

Have a great day

5 0

3 years ago