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1 year ago

Round of 1,546 to the nearest thousands

Mathematics

1 answer:

EleoNora [17]1 year ago

4 0

Answer:

1,546 ≈ 2,000

Hope this helps :)

1. To round to nearest thousands, first look at the hundreds place if the number is 1,2,3,4 then round down. If the number is 5,6,7,8,9 then round up.

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Determine whether the statement is true or false. If it is true, explain why.

Over [174]

True.

Since $y^4 \geq 0$ , $y' = -1 - y^4 \ \textless \ 0$ and the solutions are decreasing functions.

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3 years ago

I don't care about getting the answers but rather a step-by-step explanation for this problem: A simple interest, 8-month loan o

alisha [4.7K]

Answer:

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

T = 8 months = 8/12 = 2/3 years

P = $3000

R = 9.3%

Therefore

I = (3000 × 9.3 × 2/3)/100

I = 18600/100

I = $186

The maturity value (in dollars) of this loan would be

3000 + 186 = $3186

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3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

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Answer:

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It would be 100% death rates! hope this helps

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