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3 years ago

HEY PLEASE I NEED HELP IM OFFERING 30 POINTS

Mathematics

1 answer:

Levart [38]3 years ago

8 0

Answer:

the first option, (-4, 6)

Step-by-step explanation:

for this question, we can use the substitution method. this is where we substitute the coordinates in the answer choices into the given system of inequalities or equations to determine which one is true.

1. (-4,6)

x + 4y > 12

-4 + 4(6) > 12

20 > 12 is true

now we can substitute the second inequality.

3(6) > -4 + 6

18 > 2 is true, therefore making this set of points true.

it may be helpful to substitute the rest of the values of x and y into the inequalities to verify your answers :

5 + 4(2) > 12

5 + 8 > 12

13> 12 is true

3(2) > 5 + 6

6 > 11 is not true

the rest of the answer choices are also not true.

I hope this helped you!

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What is the answer to 3x-33=3

soldi70 [24.7K]

Answer:

Step-by-step explanation:

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2 years ago

Danny's jump rope is 6 meters long. How many decimeters is his jump rope?

DaniilM [7]

6 meters = 60 decimeters

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3 years ago

The sum of twice a first number and five times a second number is 78. If the second number is subtracted from five times the fir

ss7ja [257]

The numbers are: "9" and "12" .
___________________________________
Explanation:
___________________________________
Let: "x" be the "first number" ; AND:

Let: "y" be the "second number" .
___________________________________
From the question/problem, we are given:
___________________________________
2x + 5y = 78 ; → "the first equation" ; AND:

5x − y = 33 ; → "the second equation" .
____________________________________
From "the second equation" ; which is:

" 5x − y = 33" ;

→ Add "y" to EACH side of the equation;

   5x − y + y = 33 + y ;

to get: 5x = 33 + y ;

Now, subtract: "33" from each side of the equation; to isolate "y" on one side of the equation ; and to solve for "y" (in term of "x");

5x − 33 = 33 + y − 33 ;

to get: " 5x − 33 = y " ; ↔ " y = 5x − 33 " .
_____________________________________________
Note: We choose "the second equation"; because "the second equation"; that is; "5x − y = 33" ; already has a "y" value with no "coefficient" ; & it is easier to solve for one of our numbers (variables); that is, "x" or "y"; in terms of the other one; & then substitute that value into "the first equation".
____________________________________________________
Now, let us take "the first equation" ; which is:
"  2x + 5y = 78 " ;
_______________________________________
We have our obtained value; " y = 5x − 33 " .
_______________________________________
We shall take our obtained value for "y" ; which is: "(5x− 33") ; and plug this value into the "y" value in the "first equation"; and solve for "x" ;
________________________________________________
Take the "first equation":
________________________________________________
→ " 2x + 5y = 78 " ; and write as:
________________________________________________
→ " 2x + 5(5x − 33) = 78 " ;
________________________________________________
Note the "distributive property of multiplication" :
________________________________________________
a(b + c) = ab + ac ; AND:

a(b − c) = ab − ac .
________________________________________________
So; using the "distributive property of multiplication:

→ +5(5x − 33) = (5*5x) − (5*33) = +25x − 165 .
___________________________________________________
So we can rewrite our equation:

→ " 2x + 5(5x − 33) = 78 " ;

by substituting the: "+ 5(5x − 33) " ; with: "+25x − 165" ; as follows:
_____________________________________________________

  → " 2x + 25x − 165 = 78 " ;
_____________________________________________________
→ Now, combine the "like terms" on the "left-hand side" of the equation:

+2x + 25x = +27x ;

Note: There are no "like terms" on the "right-hand side" of the equation.
_____________________________________________________
→ Rewrite the equation as:
_____________________________________________________
→ " 27x − 165 = 78 " ;

Now, add "165" to EACH SIDE of the equation; as follows:

→ 27x − 165 + 165 = 78 + 165 ;

→ to get: 27x = 243 ;
_____________________________________________________
Now, divide EACH SIDE of the equation by "27" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
_____________________________________________________
27x / 27 = 243 / 27 ;

→ to get: x = 9 ; which is "the first number" .
_____________________________________________________
Now; Let's go back to our "first equation" and "second equation" to solve for "y" (our "second number"):

2x + 5y = 78 ; (first equation);

5x − y = 33 ; (second equation);
______________________________
Start with our "second equation"; to solve for "y"; plug in "9" for "x" ;

→ 5(9) − y = 33 ;

45 − y = 33;

Add "y" to each side of the equation:

45 − y + y = 33 + y ; to get:

45 = 33 + y ;

↔ y + 33 = 45 ; Subtract "33" from each side of the equation; to isolate "y" on one side of the equation ; & to solve for "y" ;

→ y + 33 − 33 = 45 − 33 ;

to get: y = 12 ;

So; x = 9 ; and y = 12 . The numbers are: "9" and "12" .
____________________________________________
To check our work:
_______________________
1) Let us plug these values into the original "second equation" ; to see if the equation holds true (with "x = 9" ; and "y = 12") ;

→ 5x − y = 33 ; → 5(9) − 12 =? 33 ?? ; → 45 − 12 =? 33 ?? ; Yes!
________________________
2) Let us plug these values into the original "second equation" ; to see if the equation holds true (with "x = 9" ; and "y = 12") ;

→ 2x + 5y = 78 ; → 2(9) + 5(12) =? 78?? ; → 18 + 60 =? 78?? ; Yes!
_____________________________________
So, these answers do make sense!
______________________________________

3 0

4 years ago

Completely factor the polynomial, if possible.

Alisiya [41]

Answer:

Complex roots [Refer picture]

Step-by-step explanation:

I am not sure if it's correct.

But we will get complex roots

8 0

3 years ago

Determine the equation from the table listed below<br><br> Will give Brainly

yanalaym [24]

Answer:

It's c) y = 15x +200

Step-by-step explanation:

First divide the total cost by the number of students using two values of the table:

1500/100 = 15

This is the number that multiply x in the equation.

In the options given, there is just one equation that have 15 multipling x, so that must be the answer

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3 years ago