Question

Suppose that a varies inversely with b^2. If a=9 when b=2, find the value of a when b=3.

Answer 1

Answer:

a = 4

Step-by-step explanation:

We can set up an equation to model this:

a = $\frac{k}{b^2}$

Now, we can plug in the information given to find the value of k:

9 = $\frac{k}{2^2}$

9 = $\frac{k}{4}$

36 = k

Now, we can find the value of a when b = 3.

a = $\frac{36}{3^2}$

a = $\frac{36}{9}$

a = 4