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marysya [2.9K]
3 years ago
8

Suppose that a varies inversely with b^2. If a=9 when b=2, find the value of a when b=3.

Mathematics
1 answer:
Archy [21]3 years ago
4 0

Answer:

a = 4

Step-by-step explanation:

We can set up an equation to model this:

a = \frac{k}{b^2}

Now, we can plug in the information given to find the value of k:

9 = \frac{k}{2^2}

9 = \frac{k}{4}

36 = k

Now, we can find the value of a when b = 3.

a = \frac{36}{3^2}

a = \frac{36}{9}

a = 4

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