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dalvyx [7]
3 years ago
10

If atmospheric pressure measurement for taking at regular intervals from sea level to the stratopause The measurements with most

likely show that the pressure
Chemistry
2 answers:
slava [35]3 years ago
6 0

Answer: Pressure decreases.

Explanation:

Atmospheric pressure is termed as the  downward force applied by the weight of air against a particular area on Earth's surface.  the Standard atmospheric pressure is determined  by weighing the column of air occupying  1 square inch on Earth's surface which begins  at sea level and moves  upward to the uppermost layer of the atmosphere

Measuring the Atmospheric pressure from sea level to the stratosphere,the second layer of the atmosphere which contains the most of the ozone gas show that the pressure decreases

Lapatulllka [165]3 years ago
5 0

Answer:

Troposphere

Explanation:

The troposphere is the lowest layer of Earth's atmosphere that extends from under the stratosphere down to the surface of the earth. Nearly all weather condition takes place in the troposphere. The troposphere contains about 75% of the atmosphere's mass and 99% of the total mass of water vapour and aerosols in the atmosphere.

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3.
asambeis [7]

Answer:

zinc forms more than one ion

3 0
3 years ago
Which is made by weathering?<br><br><br> A. sediments<br> B. minerals<br> C. ash<br> D. magma
rusak2 [61]
The answer is A cause the water breaks down the rocks into small pieces which are called sediments. These things later on turn into rocks with pressure and heat
4 0
3 years ago
How much maleic anhydride would you need to react 178 mg of anthracene? Assume 1:1 ratio from maleic anhydride to anthracene.
Licemer1 [7]

Answer:

(1) 0.10      (2) 17.8 g

Explanation:

Since the reaction ratio is 1:1 what we need is to convert the given masses to moles and you will have the answer:

MW anthracene = 178.23 g/mol

MW maleic anhydride = 98.06 g/mol

a) mass anthracene = 178 mg x 1 g/ 1000 mg = 0.178 g anthracene

Moles anthracene = 0.178 g anthracene/ 178.23 g/mol

= 0.001 mol anthracene

0.001 mol anthracene x 1 mol maleic acid/mol anthracene

= 0.001 mol maleic anhydride

mass maleic anhydride  = 0.001 mol x 98.06 g/mol =  0.10 g

b) moles maleic anhydride = 9.8 g/ 98.06 g/mol = 0.099 moles

0.099 moles maleic anhydride x 1 mol anthracene/mol  maleic anhydride =

0.099 mol anthracene

g anthracene = 0.10mol x 178 g/mol = 17.8 g

8 0
3 years ago
Acid-catalyzed dehydration of 3,3-dimethyl-2-butanol gives three alkenes: 2,3-dimethyl-2-butene, 3,3-dimethyl-1-butene, and 2,3-
Fynjy0 [20]

1,1-hexene > 2,3,3-dimethyl-2-butene > 3-methyl-3-hexene > cis-3-hexene

The Saytzeff rule states that an alkene becomes more stable the more highly substituted it is. Since 2,3-dimethyl-2-butene is the most substituted alkene among the ones listed, it will thus be the most stable.

Ozone treatment of 2,3-dimethyl but-2-ene results in ozoinde, which with further reduction yields propanone and water. Trans-2-butene undergoes ozonolysis, producing the main ozonide. Acetaldehyde, syn- and anti-acetaldehyde oxide, and this main ozonide are the products of its breakdown.

Let's not forget that the alkenes' pi bonds are least stabilized by alkyl groups, making terminal alkenes the least stable of the group. This means that among the alkenes listed, 1-hexene is the least stable.

Learn more about 2,3-dimethyl-2-butene  here brainly.com/question/24146247

#SPJ4.

5 0
2 years ago
How many mL of a stock 50% (w/v) KNO3 solution are needed to prepare 250 mL of a 20% (w/v) KNO3 solution?
Andre45 [30]

Answer:

100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.

Explanation:

In the given question it is mentioned that

     S1=50%

      V2=250ml

      S2= 20%

We all know that

                     V1S1=V2S2

                     ∴V1=  V2×S2÷S1

                     ∴V1=  V2S2×1/S1

                      ∴V1= 250×20÷50

                       ∴V1= 100ml

 

6 0
4 years ago
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