Question

2C3H6O + 8O2 --> 6CO2 + 6H2O

Answer 1

Answer: 0.45 moles of $H_2O$ will be produced from 0.15 moles of propanol.

Explanation:

The balanced chemical reaction is:

$2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O$

$C_3H_6O$ is the limiting reagent as it limits the formation of product and $O_2$ is the excess reagent.

According to stoichiometry :

2 moles of $C_3H_6O$produces = 6 moles of $H_2O$

Thus 0.15 moles of $V$ will produce=$\frac{6}{2}\times 0.15=0.45moles$  of $H_2O$

Thus 0.45 moles of $H_2O$ will be produced from 0.15 moles of propanol.