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sergey [27]
4 years ago
13

How can the atomic number and mass number be used to determine the amount of each subatomic particle present in an atom of a giv

en element?
Chemistry
1 answer:
Goshia [24]4 years ago
4 0
Because of the environment that
You might be interested in
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶M
zmey [24]

Answer:

HCl is the limiting reactant.

Explanation:

The reactant that yields the lesser number of moles of product is the limiting reactant

Number of moles of MnO2= mass of MnO2/ molar mass of MnO2

Number of moles= 37.7g/86.9368 g/mol= 0.4336 moles

From the reaction equation,

If 1 mole of MnO2 yields 1 mole of chlorine gas

0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas

For HCl

Number of moles of HCl= mass of HCl/ molar mass of HCl

Number of moles= 46.3g/36.46 g/mol = 1.27 moles of HCl

If 4 moles of HCl yields 1 mole of chlorine gas

1.27 moles of HCl will yield 1.27×1/4 = 0.3175 moles of HCl

Hence HCl is the limiting reactant.

8 0
3 years ago
Describe how is the atomic mass of an atom is calculated.<br>URGENT, NEED TO KNOW NOW!!!
padilas [110]
If it's your first encounter with chemistry, your instructor will want you to learn how to use the periodic table<span> to find the atomic mass (</span>atomic weight<span>) of an element. This number usually is given below an element's symbol. Look for the decimal number, which is a </span>weighted average of the atomic masses<span> of all the </span>natural isotopes<span> of an element. </span>
8 0
3 years ago
Balanced equation for solid magnesium oxide
Y_Kistochka [10]

Answer:

Mg + O2 → MgO

Explanation:

3 0
3 years ago
How many sig figs are in the measurment 10010m
PSYCHO15rus [73]

Answer:

5

Explanation:

They all matter unless it is a decimal.

3 0
3 years ago
How do you do this problem?
xeze [42]

Answer:

Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)

Explanation:

Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + CrO₄²⁻(aq).

Silver chromate is the salt of a strong base (AgOH) and a weak acid (H₂CrO₄).

HCrO₄⁻ is an even weaker acid than H₂CrO₄, so CrO₄²⁻ is a strong base.

Any added H⁺ will immediately combine with the chromate ions according to the reaction

H⁺ + CrO₄²⁻ ⟶ HCrO₄⁻

thereby removing chromate ions from solution.

According to Le Châtelier's Principle, more silver chromate will dissolve to replace the chromate ions that the H⁺  removes.

The overall equation for the reaction is

Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + <em>CrO₄²⁻(aq) </em>

<u>H⁺(aq) + </u><em><u>CrO₄²⁻(aq)</u></em><u> ⟶ HCrO₄⁻(aq) </u>

Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)

3 0
3 years ago
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