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nasty-shy [4]
3 years ago
14

0 (4 Зу = 4х + 15 аnd 9x + 12y = 12

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Step-by-step explanation:

please give me brainlest

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Which numerical pattern is linear?
Anna35 [415]

Step-by-step explanation:

I believe the answer is A and B

4 0
3 years ago
HELP ME [QUESTION IN IMAGE AND NOT THAT HARD EITHER]
kondaur [170]

Answer:

Button #4. The last button. 8p = t.

Step-by-step explanation:

This is because there are 8 pieces of string, and p is equal to the length of one string, so one string times 8 is the total length of all the strings.

8 0
3 years ago
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The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d
Bezzdna [24]

Answer:

0% probability that it would take exactly 3.7 hours to construct a soapbox derby car

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Also, the probability of finding an exact value in the normal probability distribution is 0.

So

0% probability that it would take exactly 3.7 hours to construct a soapbox derby car

3 0
3 years ago
R^2+6r-27 <br> factoring quadratics
Vanyuwa [196]

<em>Answer:</em>

<em>(r + 9)(r - 3)</em>

<em>Step-by-step explanation:</em>

<em>r² + 6r - 27 =</em>

<em>= r² + 9r - 3r - 27</em>

<em>= r(r + 9) - 3(r + 9)</em>

<em>= (r + 9)(r - 3)</em>

5 0
3 years ago
I neeed help doing the problem
alexgriva [62]
Her current balance aftsr adding 60$ 3 times would be -65
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4 years ago
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