Question

Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:
Initial scores: 10, 20, 30, 40
Scores after the loop: 30, 50, 70, 40
The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same.
SAMPLE OUTPUT:
#include
int main(void) {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i = 0;
bonusScores[0] = 10;
bonusScores[1] = 20;
bonusScores[2] = 30;
bonusScores[3] = 40;
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
printf("%d ", bonusScores[i]);
}
printf("\n");
return 0;
}

Answer 1

Answer:

Replace /* Your solution goes here */  with the following lines of code

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

Explanation:

The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).

Using an iterative variable, i

It adds the current element (element at i) with the next element; element at i + 1.

The full code becomes

#include<iostream>

using namespace std;

int main(void) {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i = 0;

bonusScores[0] = 10;

bonusScores[1] = 20;

bonusScores[2] = 30;

bonusScores[3] = 40;

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

/* Your solution goes here */

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", bonusScores[i]);

}

printf("\n");

return 0;

}

See attachment for .cpp file

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