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lord [1]
3 years ago
14

Which tool allows multiple users to dynamically update a document at the same time? Question 3 options: Google Docs OneDrive Exc

el Dropbox
Computers and Technology
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

Excel

Explanation:

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Something I should look for when trying to decide if a source is credible is the publication's ....
storchak [24]
Answer: Date

Explanation: We receive new information everyday, and things are always changing. If something is old, it may need to be updated with the correct information
7 0
3 years ago
Jim is expecting a very busy weekend at his store, so he sent the following e-mail to his employees: ALL EMPLOYEES MUST WORK THI
Salsk061 [2.6K]

Answer:

The caps and bold letters makes it seem like his boss is yelling at him.

Explanation:

5 0
4 years ago
Write a method that takes two circles, and returns the sum of the areas of the circles.
11111nata11111 [884]

Answer:

public static double areaSum(Circle c1, Circle c2){

 double c1Radius = c1.getRadius();

 double c2Radius = c2.getRadius();

 return Math.PI * (Math.pow(c1Radius, 2) + Math.pow(c2Radius, 2));

public static void main(String[] args){

 Circle c1 = new Circle(6.0);

 Circle c2 = new Circle(8.0);

  areaSum(c1,c2);

 }

Explanation:

7 0
3 years ago
Why does binary addition have a rule for 1 + 1 + 1 if only two numbers<br> are being added together?
dalvyx [7]

Answer:

See below

Explanation:

Because sometimes you have to 'carry' a 1 over to the ext column when adding two binary numbers

Example :

 1 1 1

<u>+1 1 1 </u>    <==== starting in the first R column add  1 + 1  to get 0 and carry 1

                then the next column you will add   1 + 1 + 1  = 1   and carry 1 again

                    then 1 + 1 + 1= 1  and carry 1 again (to column 4)  to get

1   1  1 0

5 0
2 years ago
Write the definition of a void function that takes as input an integer and outputs two times the number if it is even; otherwise
KatRina [158]

Answer:

Written in C++

void number(int n){

if(n%2 == 0)

cout<<2 * n;

else

cout<<5 * n;

}

Explanation:

The programming language is not stated.

However, I answered using C++

This line defines the function as void

void number(int n){

This line checks if the number is even

if(n%2 == 0)

If yes, it doubles the number and prints the output

cout<<2 * n;

If otherwise,

else

It multiplies the number by 5 and prints the output

cout<<5 * n;

}

To call the function from main, use:

number(n);

Note than n must be declared as integer

See attachment

Download cpp
6 0
3 years ago
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