Answer:
t= -1.33 recurring and -2
Step-by-step explanation:
3t²+4t+8=-6t
3t²+4t+6t+8
3t²+10t+8
This is a quadratic equation, it can be solved by using either factorisation, completing the square method or formulae method. For the purpose of this question, I would be using the formulae method.
-b±√(b²-4ac)/2a
Where a=3, b= 10 and c=8
-10±√(10²-4(3)(8))/2(3)
-10±√(100-96)/6
(-10±√4)/6
(-10±2)/6
-10+2/6 or -10-2/6
-8/6 or -12/6
-1.3333 recurring or -2
I'm assuming you are talking about polynomials.
For example, I have x^2 + 2x + 1, and I want to add 2x^2 + x + 2
Then the like terms here are:
x^2 and 2x^2, 2x and x, 1 and 2, they are quadratic, linear and constant, respectively.
Answer:
C)infinitely many solutions
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
