All categories

4 years ago

. An experiment shows that the element

Mathematics

2 answers:

sergiy2304 [10]4 years ago

7 0

Answer:

Step-by-step explanation:

D=m/v

Rearranging the formula

v=m/D

V=1000/13.56

V=73.69 cm3

Anestetic [448]4 years ago

4 0

Answer:

v = 73.69 cm²

Step-by-step explanation:

V = m/p

Where,

v is volume

m is mass

p is density

So,

v = 1000 / 13.57

v = 73.69 cm²

I believe that this maybe a wrong answer because 1000 kg is suppose to be converted to g but since the answer (which is 73692 cm³) would not meet any of the options, I would have to go for that answer.

You might be interested in

The number of ball hoppers f(t) needed to hold tennis balls for a tournament can be found using function f(t) = t/75. If there a

Alina [70]

Answer:

Step-by-step explanation:

4 0

3 years ago

I need to get aleks done on june 30th

Kazeer [188]

Pretty much saying 5+ (x*10)_<-25

3 0

3 years ago

Read 2 more answers

Allushta [10]

The answer is 99.7 percent of chimpanzees

3 0

3 years ago

Urgent as i have final soon. How to solve problems like this f( ) = 8x+29

Kaylis [27]

Answer:

See below

Step-by-step explanation:

we have f(x) = 8x + 29

essentially f(x) is a function and the number that goes in the blank is the input, whatever the input is you plug in to all values of x and evaluate to get the output

we are going to assume that we have to solve for f(4)

so we have f(4) = 8x + 29

because 4 is in the "input spot" we input a 4 for every x we see in the function

So we get f(4) = 8(4) + 29

we then simply evaluate

f(4) = 8(4) + 29

==> multiply 8 and 4

f(4) = 32 + 29

==> add 32 and 29

f(4) = 61

So if the input of f(x) was 4, the out put would be 61

Let me know if you have any further questions! :)

7 0

2 years ago

Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the pr

Ratling [72]

Answer:

The probability that of the two chips selected both are defective is 0.1089.

Step-by-step explanation:

Let X = number of defective chips.

It is provided that there are 2 defective chips among 6 chips.

The probability of selecting a defective chip is:

$P(X)=p=\frac{2}{6}=0.33$

A sample of n = 2 chips are selected.

The random variable X follows a Binomial distribution with parameter n = 2 and p = 0.33.

The probability function of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...$

Compute the probability that of the two chips selected both are defective as follows:

$P(X=2)={2\choose 2}(0.33)^{2}(1-0.33)^{2-2}=1\times 0.1089\times 1=0.1089$

Thus, the probability that of the two chips selected both are defective is 0.1089.

The sample space of selecting two chips is:

S = (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

3 0

3 years ago