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Furkat [3]
3 years ago
7

What is the Product of x-3 and x-9​

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

x^2-12x+27

Step-by-step explanation:

(x-3)(x-9)=x^2-3x-9x+27=x^2-12x+27

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27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8
Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

27^x=9^{x-4}

Note that

27=3^3\\ \\9=3^2,

then

27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}

Rewrite the equation as

3^{3x}=3^{2(x-4)},

then

3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8

4 0
3 years ago
70% of a number is 98.
hammer [34]
The solution is as follows:

Set up the proportion:

70% - 98
90% - x

70% / 90% = 98 / x

7 / 9 = 98 /x

(7 / 9) x = 98

x = 98 x 9/7

x = 14 x 9

x = 126

The answer is <span>D. 126.


I hope my answer has come to your help. God bless and have a nice day ahead!</span>
8 0
3 years ago
A body was found at 10 a.m. in a warehouse where the temperature was 40F. The medical examiner found the temperature of the body
lawyer [7]
Newton's law of cooling states that under forced convection (which is assumed to be true), then
dT(t)/dt = -k(T(t)-Ta)..............(1)
T(t)=temperature
Ta=ambient temperature=40F
k=cooling constant = 0.1947
T(0)=98.6F (assuming victim did not have fever)
Integrate (1)
T(t)-Ta=(T(t)-T(0))e^(-kt)
Solve for t
(T(t)-Ta)/(T(t)-T(0)) = e^(-kt)
take log:
-kt=log_e((T(t)-Ta)/(T(t)-T(0)))
substitute T(t)=80F, Ta=40F,T(0)=98.6F
-kt=log_e((80-40)/(98.6-40))=-0.38186
t=0.38186/0.1947
=1.96, or almost 2 hours   (assuming k=0.1947 is in hours)
7 0
3 years ago
Read 2 more answers
The ratio of the width to the length of a rectangular garden is 2 to 3. Which of the following could be the width and length of
ANTONII [103]
The only one has a ratio of 2:3 is D. 
8 0
3 years ago
Rectangle Q has an area of two square units. Thea drew a scaled version of rectangle Q and labeled it rectangle R. what scale fa
belka [17]

Answer:

It is given that Rectangle Q has an area of 2 square units.

Thea Drew a scaled version of Rectangle Q and marked it as R.

As you must keep in mind If we draw scaled copy of pre-image, then the two images i.e Pre-image and Image are similar.

As you have not written what is the scale factor of transformation

Suppose , Let the Scale factor of transformation= k

Rectangle Q = Pre -image, Rectangle R= Image

If, Pre-Image < Image , then scale factor is k >1.

But If, Pre-Image > Image , then Scale factor will be i.e lies between, 0<k<1.



3 0
3 years ago
Read 2 more answers
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