Answer is
Point-slope form: y + 1 = 4(x -1)
Assuming you wanted
Slope-intercept form: y = 4x -5
Step by step
y - - 1 = 4(x -1)
y + 1 = 4(x -1)
y + 1 = 4x -4
y = 4x -5
Let x=the first number
Then x+7=second number
And 4(x+7)+2=third number (2 more than 4 times the second)
Now we are told that:
x+(x+7)+(4(x+7)+2)=85 get rid of parentheses
x+x+7+4x+28+2=85 simplify
6x+37=85 subtract 37 from each side
6x+37-37=85-37
6x=48
x=8---first number
x+7=8+7=15 second number
4(x+7)+2=4*15+2=62 third number
CK
8+15+62=85
85=85
Answer:
No
Step-by-step explanation:
Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.
Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't
If something is a function, every x-value, only has one (1) y-value. If the line x = 0 intersects the graph in two points, there are to values for y (instead of one). Therefore the graph is not a function of x.
Your answer is A.
