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katrin [286]
2 years ago
13

Find the value of t.

Mathematics
2 answers:
zaharov [31]2 years ago
5 0

Answer:

t =12 m

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem.

Put the smaller triangle on top and the larger triangle on bottom

12         9

------ = -------

16          t

Solve by using cross products

12 t = 9*16

12 t =144

Divide by 12

12t/12 = 144/12

t = 12

Dmitriy789 [7]2 years ago
5 0

\text{We have similar right triangles (Acute Angle Similarity)}\triangle BAC\sim\triangle BED\\\\\dfrac{BA}{AC}=\dfrac{BE}{ED}\\\\\text{We have}\\\\BA=12m,\ AC=9m,\ BE=16m,\ ED=t.\\\\\text{Substitute:}\\\\\dfrac{12}{9}=\dfrac{16}{t}\qquad\text{cross multiply}\\\\12t=(9)(16)\\\\12t=144\qquad\text{divide both sides by 12}\\\\\boxed{\boxed{t=12\ m}}. Therefore the legs make proportions.


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Angelina_Jolie [31]
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The equation we have is:
5,249 = 29d
If they read 5,249 <em>pages</em>, then we can include the unit for pages in the equation.
Since we also know that <em>d</em> is the number of days it took, you can replace <em>d</em> with days.
The equation becomes:
5,249\ pages=29*(x\days)
Now that we have one variable, we can solve for <em>p/d</em>:
\frac{5,249\ pages}{29}=x\ days\\\\181 = x
Thus it took them 181 days to read it all.

If Johnny read 5,249 pages over 181 days and the unit rate is pages per day(p/d), then the equation for finding <em>p/d</em> is:
\frac{p\ pages}{d\ days}=\frac{5,249\ pages}{181\ days}=\frac{29\ pages}{1\ day}\\\\29\ \frac{pages}{day}
Johnny read 29 pages per day.
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below is a graph of a logarithmic function, identify it key characteristics. match accordingly.that is the question and can you
Zolol [24]

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Transformation: l. right 2

with respect to the next parent function:

g(x)=\log _{\frac{1}{3}}(x)

Domain: g. x > 2

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1 year ago
As you can see I keep getting questions wrong.... Can you answer the last question?
aivan3 [116]

Answer:

  y = 0

Step-by-step explanation:

It is always a good idea to look at the question and make some observations about it. Here, you might observe ...

  • all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
  • y is a factor of every exponent

The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.

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To solve the equation, you can write it in terms of powers of 3.

  (3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)

  3^(-5y) = 3^(-15y)·3^(-4y)

  3^(-5y) = 3^(-19y)

  -5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3

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4 0
3 years ago
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3 years ago
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
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