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julia-pushkina [17]
2 years ago
6

A bingo card has 25 spaces but 1 free space, and if the card deck is 100 cards how do i know how many game cards i need for play

ers to have?​
Mathematics
1 answer:
german2 years ago
5 0

Answer:

Step-by-step explanation:

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Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft. 3 12 ft.3. Myla has a storage box that is 4 ft
Alex17521 [72]

Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.

Step-by-step explanation:

Formula : Volume of cuboidal box = length x width x height

width=\dfrac{Volume}{length\times height}

Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .

width=\dfrac{12}{2\times3}=2\ ft.

Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.

width=\dfrac{16}{4\times2}=2\ ft.

Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.

4 0
3 years ago
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Naddika [18.5K]

Answer:

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6 0
3 years ago
Please help me solve all of these for M and B.
erastovalidia [21]

Answer:

In number 1:

m = 10/3

b = 19

Step-by-step explanation:

To find the answers to these, simply look to the coefficient of x and the constant at the end of the equation. The number attached to x is always m (which is known as the slope). The number at the end is b (or the y-intercept).

6 0
3 years ago
Brian started working at Domino’s in order to build his savings account. He started off with $33 dollars in his account, then ev
iragen [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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