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3 years ago

Find the length of side BY for the given triangle.

Mathematics

1 answer:

saul85 [17]3 years ago

3 0

Answer:

option 3- 5 square root 2

Step-by-step explanation:

$\sin 45° = \frac{BY}{OY} \\ \\ \frac{1}{ \sqrt{2} } = \frac{BY}{10} \\ \\ BY = \frac{10}{ \sqrt{2} } \\ \\ BY = \frac{10 \times \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } \\ \\ BY = \frac{10 \sqrt{2} }{2 } \\ \\ \huge \red{ \boxed{BY = 5 \sqrt{2} }}$

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A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper

MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f) P ( T' | N ) = 0.32258

g) P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

We are asked for a conditional probability of the form as follows:

P ( R' | T ) = P ( R' & T ) / P ( T )

First compute the probability that next news source is not Radio provided it is already a source of TV.

P ( R' & T ) = P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

P ( R' | T ) = 0.44 / 0.7

P ( R' | T ) = 0.62857

- Now for part f)

We are asked for a conditional probability of the form as follows:

P ( T' | N ) = P ( T' & N ) / P ( N )

First compute the probability that next news source is not TV provided it is already a source of Newspaper.

P ( T' & N ) = P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

P ( T' | N ) = 0.2 / 0.62

P ( T' | N ) = 0.32258

- Now for part g)

We are asked for a conditional probability of the form as follows:

P ( R' | N ) = P ( R' & N ) / P ( N )

First compute the probability that next news source is not Radio provided it is already a source of Newspaper.

P ( R' & N ) = P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

P ( R' | N ) = 0.44 / 0.62

P ( R' | N ) = 0.70968

- Now for part h)

We are asked for a conditional probability of the form as follows:

P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.

P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

P ( T' | N&R ) = 0.15 / 0.18

P ( T' | N&R ) = 5/6

6 0

3 years ago

A car travels at 65 miles per hours. Going through construction it travels at 3/5 this speed. Write this fraction as a decimal a

olga nikolaevna [1]

3/5 = 6/10 = 0.6
0.6×65=39
Car travels 39 miles per hour through construction.

6 0

3 years ago

Which equation can be used to represent the statement?

Luba_88 [7]

Answer:

4. One-sixth n minus 2 = negative two-thirds

Step-by-step explanation:

4 0

3 years ago

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The surface area of the pyramid with square base that measures 8 ft by 8 ft and slant height of 12 ft is 256 ft^2.

Maru [420]

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5 0

3 years ago

As the limit of x goes to 3 from the left find the limit of (x/ sqrt x^2 -9)

Dimas [21]

$\displaystyle\lim_{x\to3^-}\frac x{\sqrt{x^2-9}}=\lim_{x\to3^-}\frac x{\sqrt{x^2}\sqrt{1-\frac9{x^2}}}=\lim_{x\to3^-}\frac x{|x|\sqrt{1-\frac9{x^2}}}$

Since $x>0$ , you have $|x|=x$ and the limand reduces to

$\displaystyle\lim_{x\to3^-}\frac1{\sqrt{1-\frac9{x^2}}}$

For $x>3$ , you have $\sqrt{1-\frac9{x^2}}>0$ since $\dfrac9{x^2}$ will always be smaller than 1, which means $\dfrac1{\sqrt{1-\frac9{x^2}}}\to+\infty$

8 0

4 years ago