Which of the following graphs represents the solution set for the inequali -35-2x +1 <11
1 answer:
Answer:
You did not give the options, so i just will graph it.
The inequality is:
-35 - 2*x + 1 < 11.
Now we would want to isolate the x in one side, so we can start by adding 35 in both sides.
(-35 -2*x + 1) + 35 < 11 + 35
-2x + 1 < 46
now we can subtract 1 in both sides:
-2x + 1 - 1 < 46 - 1
-2x < 45
Now we can divide by -2, remember that if we multiply or divide by a negative number, then the "direction" of the sign changes.
(-2x)/-2 > 45/-2
x > -22.5
Then the graph of the set is an open dot at the point x = -22.5 (this means that the set does not include this point) and a line that extends to the right. (Extends to the right because x is larger than -22.5)
Below is an example of how to draw the graph that represents the set of solutions.
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Using the normal distribution, it is found that:
1. His z-score was of Z = -1.88.
2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.
3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.
4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.
<h3>Normal Probability Distribution</h3>In a normal distribution with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of
.
- The standard deviation is of
.
Item 1:
Considering his ratio, we have that X = 0.73, hence:
His z-score was of Z = -1.88.
Item 2:
The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.
Item 3:
Score of X = 1.96, hence:
The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.
Item 4:
Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.
More can be learned about the normal distribution at brainly.com/question/24663213