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lyudmila [28]
3 years ago
12

T(x) = ax^5 + 2 where is a real number. If the points (-2, 66) and (2, -62) are on the graph of the function classify as one of

the following.
0 < a < 1
a < -1
a > 1
0 > a > -1
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer:

a < -1

Step-by-step explanation:

Okay, so we are given this equation:

t(x) = ax^5 + 2

Lets plug in -2 as x and see what happens.. t(x) can be 66..

a * (-2)^{5}  + 2 = 66

-32a + 2 = 66

-32a = 64

a = -2

A is less than -1,

a < -1

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