All categories

3 years ago

Choose the equation that best fits the following graph.

Mathematics

1 answer:

Lisa [10]3 years ago

6 0

Answer:

c. y = 3.25^x

Step-by-step explanation:

At x=1, the value of y is slightly more than 3, so the base must be more than 3. The appropriate choice is ...

y = 3.25^x

You might be interested in

Anne deposited $500 in an account that earns 6% simple annual interest. Shelly deposited $500 in an account that earns 6% annual

Inga [223]

Answer:

It is clear that, The Shelly account is $11.23 more than that in Anne account .

Step-by-step explanation:

Given as :

For Anne

The amount deposited in account = p = $500

The rate of interest = r = 6% at simple interest

The time period of deposit = t = 4 years

Let The amount received in account after 4 years = $ $A_1$

From Simple Interest method

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, s.i = $\dfrac{\textrm 500\times \textrm 6\times \textrm 4}{100}$

Or, s.i = $\dfrac{12000}{100}$

i.e s.i = $120

∵ Amount = Principal + Interest

Or, $A_1$ = p + s.i

Or $A_1$ = $500 + $120

Or, Amount = $620

So, The Amount in Anne account after 4 years is $620

Again

For, Shelly

The amount deposited in account = P = $500

The rate of interest = R = 6% compounded annually

The time period of deposit = T = 4 years

Let The amount received in account after 4 years = $ $A_2$

From Compound Interest method

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, $A_2$ = P × $(1+\dfrac{\textrm R}{100})^{\textrm T}$

Or, $A_2$ = $500 × $(1+\dfrac{\textrm 6}{100})^{\textrm 4}$

Or, $A_2$ = $500 × $(1.06)^{4}$

Or, $A_2$ = $500 × 1.26247

Or, $A_2$ = $631.23

So, The amount received by Shelly in her account after 4 years = $631.23

Now, Difference between amount received in their account

i.e $A_2$ - $A_1$ = $631.23 - $620

Or, $A_2$ - $A_1$ = $11.23

Hence, It is clear that, The Shelly account is $11.23 more than that in Anne account . Answer

8 0

3 years ago

Find the area of each shade region (can you do both for me please)

grandymaker [24]

*FORMULA*

Qu1.

$area \: of \: a \: triangle = \frac{1}{2} base \: \times height$

Height=10

Base=8

$= \frac{1}{2} \times 8 \times 10$

$= 40$

Qu2.
Area of a kite=half×product of digonals
Step by step solution
Summation of 1st diagonal =5+5
=10
Summation of 2nd diagonal =7+5
=12
Product of the diagonals
=10×12
=120
Area=1÷2×120
=60

3 0

4 years ago

Read 2 more answers

Which choice answer is it?

Debora [2.8K]

Your answer would be option (1) -3x² - 18x + 19.

To find this we need to substitute in the G and F expressions into G - 3F and see what the outcome is, as this will give us the answer.

First I’m going to multiply the F expression, 2x² + 6x - 5, by 3:

3 × (2x² + 6x - 5) = 3(2x²) + 3(6x) - 3(5) = 6x² + 18x - 15.

Now we need to subtract this expression from G, which is 3x² + 4, which I will do by term:

3x² - 6x² = -3x²

0x - 18x = -18x

4 - -15 = 19

So therefore overall your answer is -3x² - 18x + 19.

I hope this helps! Let me know if you have any questions :)

8 0

3 years ago

26 was divided by a power of ten to get 0.26. What power of ten was it divided by?

Inga [223]

100

I got the answer by 26 divided by 0.26

3 0

3 years ago

How many solutions does this system of equations have 5m-4=7m+8

Stels [109]

Find value of m either add or subtract for m

5 0

3 years ago

Choose the equation that best fits the following graph.​

Choose the equation that best fits the following graph.