Answer:
a) 

b) From the central limit theorem we know that the distribution for the sample mean
is given by:
c)
Step-by-step explanation:
Let X the random variable the represent the scores for the test analyzed. We know that:

And we select a sample size of 64.
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Part a
For this case the mean and standard error for the sample mean would be given by:


Part b
From the central limit theorem we know that the distribution for the sample mean
is given by:
Part c
For this case we want this probability:

And we can use the z score defined as:

And using this we got:
And using a calculator, excel or the normal standard table we have that:
7 1\5=7x5+1=36\5
36\5 x 100=720%
120 is the right answer that is what my teacher told me
PR=18mm
AB=7mm
All lengths of triangle PRQ are twice the lengths of ACB
You just do 40 times 0.825 and you will get your answer.