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LUCKY_DIMON [66]
3 years ago
5

Dos agricultores, padre e hijo, tardan 2 horas entre los dos arar un campo. Si solo el padre tarda 6 horas. ¿Cuanto tardara el h

ijo?
Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

El hijo solo tardará 3 horas en arar el campo

Step-by-step explanation:

Aquí, se nos dice que ambos pasan dos horas para arar el campo mientras que el padre solo pasa 6 horas.

Queremos saber el tiempo que pasará el hijo si va a trabajar solo

Sea el área del campo x

La tasa de trabajo de ambos es x / 2

La tasa de trabajo del padre será x / 6 Deja que el tiempo que pasa el hijo sea y La tasa de trabajo del hijo es x / y

Sumando la tasa de trabajo del padre a la del hijo da la tasa de trabajo total de ambos Por lo tanto;

x / 6 + x / y = x / 2

Despegar x 1/6 + 1 /y = 1/2

1 / y = 1/2 - 1/6

1 / y= 1/3

entonces y = 3

El hijo solo tardará 3 horas en arar el campo.

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tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
2 years ago
Find the slope of the line passing through the points (-6,2), (0,-6).
Serhud [2]

C. -4/3

slope =  \frac{(y _{2} - y _{1}) }{(x _{2} - x _{1} )}  \\  =  \frac{( - 6 - 2)}{(0 -( -  6)}  \\  =  \frac{ - 8}{ 6}  \\  =   - \frac{4}{3}

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I<br> 216<br> Solve the linear equation.<br> 9x - 9 = 5x + 19<br> x=-7<br> x = 7<br> x = 5<br> x = 2
const2013 [10]

Answer:

x=7

Step-by-step explanation:

9x-9=5x+19

Combine like terms

9x-5x=19+9

4x=19+9

4x=28

x=7

5 0
3 years ago
Find the slope of the line passing through the two points.
pogonyaev
Formula for slope: y2-y1/x2-x1
Plug in values. 
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50 POINTS please only a correct answer
labwork [276]

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7 0
3 years ago
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