Answer:
7d - 28
Step-by-step explanation:
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
GCF is Greatest Common Factor and LCM is Least Common Multiple
rise/run y=1
raise the point up 1 and place a point
then from that point count up four and across 3 (right) and place another point there
Answer:
50x
Step-by-step explanation:
The 17 is the loop product or 6. Do reverse division and add the 78 on step three. Good Luck!
