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marusya05 [52]
3 years ago
13

The graph of a proportional relationship passes through (9, 18) and (1, y). Find y.

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Because it's a proportional relationship and it goes through the point (9, 18) the equation is y = 2x so when x = 1, y = 2.

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GarryVolchara [31]

Answer:

1. 0

2. undefined

3. -3/2

Step-by-step explanation:

y=-3/2. This value is constant and the x does not change the value at all. so the coordinate are going to be (x, -3/2) so if we take any 2 values you're going to get (-3/2 - (-3/2)) / (x2 - x1) = (-3/2 + 3/2) / (x2 - x1) = (0) / (x2 - x1) which is always going to be 0.

x=-3/2. This value is also constant except the x-value does not vary at all so x2 and x1 are always going to be equal which will result in a 0 as the denominator thus making the slope undefined

y=-3/2x. it's just -3/2 given the slope-intercept form y=mx+b where m is the slope

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GuDViN [60]

Answer:

63

Step-by-step explanation:

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Ap Calc bc. Need help keep getting this question wrong
kupik [55]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

Step 3:

Now, from the solution above, we can see that the value of the integrand CONVERGES to a number that is approximately 0.41634

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10 months ago
3.1+k=5.67 <br> t+20.04=14.3<br> SOLVE!!!
makkiz [27]
The answer is


K= 2.57
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Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
Sauron [17]

Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

8 0
3 years ago
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