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Archy [21]
3 years ago
12

Suppose you pick and replace marbles from a bag, one after another. If the bag

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

1/8

Step-by-step explanation:

There are 3 + 3 + 6 = 12 marbles in the bag and 12 * 12 = 144 ways to choose two marbles when replacing. There are 3 * 6 = 18 ways to choose a red marble and then a blue marble so the probability is 18 / 144 = 1 / 8.

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What are the zeros of f(x) = x2+x-20?
Zielflug [23.3K]

Answer:

The zeros are (-5,0) and (4,0)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Tommy stands on a diving board that is 4 fee above the pools surface. He dives and touches the bottom of the pool, which is 12 f
vladimir1956 [14]
12*4=48 that is because you have to times 12*4 
8 0
3 years ago
Dont really understand how to do this
bija089 [108]

Answers:

t_{10} = -22 \ \text{ and } S_{10} = -85

========================================================

Explanation:

t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4

and so on. This process may take a while to reach t_{10}

There's a shortcut. The nth term of any arithmetic sequence is

t_n = t_1+d(n-1)

We plug in t_1 = 5 \text{ and } d = -3 and simplify

t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8

Then we can plug in various positive whole numbers for n to find the corresponding t_n value. For example, plug in n = 2

t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2

which matches with the second term we found earlier. And,

tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}

---------------------

The notation S_{10} refers to the sum of the first ten terms t_1, t_2, \ldots, t_9, t_{10}

We could use either the long way or the shortcut above to find all t_1 through t_{10}. Then add those values up. Or we can take this shortcut below.

Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}

The sum of the first ten terms is -85

-----------------------

As a check for S_{10}, here are the first ten terms:

  • t1 = 5
  • t2 = 2
  • t3 = -1
  • t4 = -4
  • t5 = -7
  • t6 = -10
  • t7 = -13
  • t8 = -16
  • t9 = -19
  • t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that S_{10} = -85 is correct.

6 0
2 years ago
How do I solve this? Step by step
shutvik [7]

Answer:

24.

Step-by-step explanation:

Substitute each instance of x with a 3.

That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.

Combine like terms.

2(3^2) + 6.

Simplify.

2(9) + 6

18 + 6

24.

8 0
3 years ago
Read 2 more answers
Marc wants to guess how many marbles are in a box that has a height of 18 inches. He calculates that there are 32 marbles in a h
Rainbow [258]

So every 5 inches in height, there are 32 marbles. You want to know how many marbles there are per 18 inches in height.

\frac{32}{5} = \frac{x}{18}

To get from 5 to 18, you multiply by 3.6.

Do the same thing to the numerator; 32 × 3.6 = 115.2.

Since 0.2 marbles is no marbles, you round down.

There are 115 marbles in the box.

♡ Hope this helps! ♡

❀ 0ranges ❀

8 0
2 years ago
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