The solution of the system of equations is (6 , -7)
Step-by-step explanation:
There are two method to solve the system of equations
- Elimination method: we make the coefficients of one variable in the two equations have same values and different signs, then we add the two equations to eliminate this variable and have an equation of other variable, we solve it to find the other variable, then substitute the value of this variable in one of the two equations to find the first variable
- Substitution method: We use one of the two equations to find one variable in terms of the other, then substitute it in the second equation to have an equation of the other variable, we solve it to find the other variable, then substitute the value of this variable in the equation of the first variable
Let us use the elimination method with your problem
∵ 3x + 2y = 4 ⇒ (1)
∵ 3x + 6y = -24 ⇒ (2)
- Multiply equation (1) by -1 to eliminate x ⇒ to make the coefficients of x in the two equations have same values and different signs
∵ -3x - 2y = -4 ⇒ (3)
- Add equations (2) and (3)
∴ 4y = -28
- Divide both sides by 4
∴ y = -7
Substitute value of y in equations (1) OR (2) to find x
∵ 3x + 2(-7) = 4
∴ 3x - 14 = 4
- Add 14 for both sides
∴ 3x = 18
- Divide both sides by 3
∴ x = 6
The solution of the system of equations is (6 , -7)
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D. Use FOIL and guess and check to factor the equation
Answer:
28/9
Step-by-step explanation:
If the roots are J and K, then:
3 (x − J) (x − K) = 0
3 (x² − (J+K)x + JK) = 0
So if we factor out the leading coefficient:
3x² − 2x − 4 = 0
3(x² − 2/3x − 4/3) = 0
The coefficient of the second term is the sum of the roots:
J + K = 2/3
And the constant is the product of the roots:
JK = -4/3
If we take the sum of the roots and square it:
(J + K)² = (2/3)²
J² + 2JK + K² = 4/9
And subtract twice the product:
J² + K² = 4/9 − 2JK
J² + K² = 4/9 − 2(-4/3)
J² + K² = 4/9 + 8/3
J² + k² = 28/9
Answer:
Option D (the weight of crab) would be the correct choice.
Step-by-step explanation:
- In mathematics, the sum being analyzed depending on a variety of parameters, which have been calculated as explanatory variables, has become a response variable.
- It is analogous with the utilization of the definition of variables of the study. A variable with an order to respond is categorized as either a dependent variable.
Some other preferences are not connected with the sustaining. So choice D is the right one.