6.16441 which rounds to 6.2 in the tenths place
Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
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Information Given:
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ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7
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Since it is a parallelogram:
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ON = LM and
MN = OL
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ON = LM:
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7x - 9 = 6x + 4
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Subtract 6x from both sides:
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x - 9 = 4
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Add 9 to both sides:
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x = 13
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MN = OL:
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x - 7 = 2y - 7
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Sub x = 13:
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13 - 7 = 2y - 7
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Simplify:
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6 = 2y - 7
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Add 7 on both sides:
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13 = 2y
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Divide by 2:
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y = 13/2
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Answer: x = 13, y = 13/2 (Answer D)
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Answer:
Thx for the points
Step-by-step explanation:
