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alekssr [168]
3 years ago
13

What is the first ordered pair and the second ordered pair?

Mathematics
1 answer:
Delvig [45]3 years ago
7 0
When x=-5, y=(1/5)*(-5)-1=-2, so the first order pair is (-5,-2)
when y=-1, -1=(1/5)x-1, (1/5)x=0, x=0, so the second ordered pair is (0, -1)
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Answer:

-4,-3,-2,-1,0,1

Step-by-step explanation:

First, doublepound and simplify it.

-15<3n

3n<6

Solve:

-5<n

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Compound:

-5<n<2.

So the values are -4,-3,-2,-1,0,1

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Use the substitution method to solve the system of equations. Choose the correct ordered pair. 2x + y = 10 y = x – 5 A. (5, 0) B
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3 years ago
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If f ( x ) f(x) is an exponential function where f ( − 3.5 ) = 25 f(−3.5)=25 and f ( 6 ) = 33 f(6)=33, then find the value of f
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Given:

f(x) is an exponential function.

f(-3.5)=25, f(6)=33

To find:

The value of f(6.5).

Solution:

Let the exponential function is

f(x)=ab^x         ...(i)

Where, a is the initial value and b is the growth factor.

We have, f(-3.5)=25. So, put x=-3.5 and f(x)=25 in (i).

25=ab^{-3.5}         ...(ii)

We have, f(6)=33. So, put x=6 and f(x)=33 in (i).

33=ab^{6}         ...(iii)

On dividing (iii) by (ii), we get

\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}

1.32=b^{9.5}

(1.32)^{\frac{1}{9.5}}=b

1.0296556=b

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Putting b=1.03 in (iii), we get

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33=a(1.194)

\dfrac{33}{1.194}=a

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Putting a=27.63 and b=1.03 in (i), we get

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