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2 years ago

ITS DUE TODAY! HELP ME PLEASE

Mathematics

1 answer:

Brums [2.3K]2 years ago

8 0

Mean - 4.19

median - 4

modes - 0,1,1,2,2,3,3,3,3,3,4,4,5,5,5,6,7,7,7,8,9

range - 9

interquartile range - 4

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X/7- y/5=1 solve for y

Usimov [2.4K]

Answer:

y = 5/7 x -5

Step-by-step explanation:

X/7- y/5=1

Multiply each side by 35 to clear the fractions

35(X/7- y/5) =1*35

5x - 7y = 35

Subtract 5x from each side

5x-5x-7y = -5x+35

-7y = -5x+35

Divide each side by -7

-7y/-7 = -5x/-7 +35/-7

y = 5/7 x -5

4 0

2 years ago

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the temperature 0 F ,3 F ,6 F ,5 F,and -1 F have also been recorded in florida .graph these temperature on the number line .

Brut [27]

-1F, 0F, 3F, 5F, 6F Think of this as a normal number line -3 -2 -1 0 1 2 3
hope this helped

4 0

2 years ago

Explain the difference between evaluating 3 * 7 - 4 ÷ 2 and evaluating 3(7 - 4) ÷ 2.

Bogdan [553]

DIY. I believe in you, its just a matter if you believe in yourself. Your welcome

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2 years ago

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I WILL MARK YOU AS BRANLIEST JUST DO THIS PLS ASAP

tensa zangetsu [6.8K]

Answer:

(6t) + (3t) + (4t)

Simplified it would be 13t

3 0

2 years ago

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

2 years ago