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Naddika [18.5K]
3 years ago
8

The salaries of three employees are listed below. Each employee was recently given a raise. Which amount is closest to the total

of all three raises?

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

A

Step-by-step explanation:

We take the percentage raise and convert to decimal by dividing by 100. Then multiply this with the salary before raise. This will give us the "raise amount".

Then we will add up all of the "raises" of 3 employees to get our answer.

Jane = 4/100 = 0.04

0.04*41,500 = 1660

John = 4.5/100 = 0.045

0.045 * 44,100 = 1984.5

Jack = 3/100 = 0.03

0.03 * 39,600 = 1188

Sum of all 3 raises:

1660 + 1984.5 + 1188 = $4832.5

From the answer choices, A is the closest, $4833

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Scientific notation is used so that the order of the number is known in first glance. The value of the given number in scientific notation is given by: Option B: 6.9 \times 10^{-6}

<h3>How does scientific notations work?</h3>

The number is written in the form a \times 10^b where we have 1 \leq a < 10

The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10. We can for a time, ignore the value of 'a' for two comparable quantities and only compare their orders(this type of comparison is useful when difference is too big, like size of human to size of a star etc sort of comparisons).

Scientific notations have some of the profits as:

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For the given case, the number in consideration is 0.0000069

Rewriting it in fraction form, we get:

0.0000069  = \dfrac{69}{10000000} = \dfrac{69}{10^7} = 69 \times 10^{-7} = 6.9 \times 10 \times 10^{-7}\\\\0.0000069  =  6.9 \time 10 ^{-7 +1} \\0.0000069  = 6.9\times 10^{-6}

(we used two facts: first that : \dfrac{a}{b} = a \times \dfrac{1}{b}

and second that: a^{-b}= \dfrac{1}{a^b}

Thus, the value of the given number in scientific notation is given by: Option B: 6.9 \times 10^{-6}

Learn more about scientific notations here:

brainly.com/question/3112062

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