Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Volume of a cone = (1/3) x Area of the base (B) x height(h)
V = (1/3)·420·180
= 25200 mm³
Answer:

Step-by-step explanation:
Here, the given expressions are:
A) 
Solving this, we get

⇒
B) 
Now, solving this, we get

⇒
C) 
Simplifying this, we get

⇒ 
I'll solve it algebraically
x+y=4
x-3y=12
multiply first equatoin by -1 and add to second
-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=4
x+-2=4
add 2 to both sides
x=6
x=6
y=-2
(6,-2)
Answer:
1206
Step-by-step explanation:
find the pattern and add. ;)