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4 years ago

Check if correct if it's not identify and simplify to find correct answer

Mathematics

1 answer:

xz_007 [3.2K]4 years ago

3 0

Yes u r correct if u need more help pm me i will be gladly to help u

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Suppose you have a standard deck of 52 cards. What is the probability that if you select a card at random that it does not have

mr Goodwill [35]

0.92

Step-by-step explanation:

There are 4 cards in a deck of 52 cards that has a face value of 3. That means that the other 48 cards don't have a face value of 3. Therefore, the probability of picking a card of this deck that doesn't have a face value of 3 is

$P =\dfrac{48}{52} = 0.92$

4 0

3 years ago

The ratio of the areas of two similar polygons is 64:36. if the perimeter of the first polygon is 35 cm, what is the perimeter o

konstantin123 [22]

105/4
because the ratio of the perimeter of the first to second is 4/3

5 0

3 years ago

Find the area of the shaded region

KengaRu [80]

Answer:

36 square units

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Y * x = 20<br><br> y + x = 9 <br><br> what numbers are y and x equal to?

Ksivusya [100]

$y = 9 - x$
Substitute into
$y \times x = 20 \\ (9 - x) \times x = 20 \\ { - x}^{2} + 9x = 20 \\ {x}^{2} - 9x + 20 = 0 \\ (x - 5)(x -4) = 0 \\ x = 5 \: or \: x = 4$
When x = 5,
$y = 9 - 5 \\ y = 4$
When x = 4,
$y = 9 - 4 \\ y = 5$

x = 5, y = 4
x = 4, y = 5

Hope this helps. - M

4 0

3 years ago

A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len

aniked [119]

Answer:

a. V = (20-x) $x^{2}$ $in^{3}$

b . 1185.185 $in^{3}$

Step-by-step explanation:

Given that:

The height: 20 - x (in )
Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h * $x^{2}$ $in^{3}$

<=> V = (20-x) $x^{2}$ $in^{3}$

b. What is the maximum possible volume of the box?

To maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3 $x^{2}$ + 40x

Let dV / Dx = 0, we have:

-3 $x^{2}$ + 40x = 0

<=> x = 40/3

=>the height h = 20/3

So the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 $in^{3}$

7 0

3 years ago