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Margaret [11]
2 years ago
14

A 5,000 principal is invested into two accounts, one earning 1% and another earning 6% interest. If the total interest for the y

ear is $170, how much is invested in each?
Mathematics
1 answer:
tia_tia [17]2 years ago
4 0

Answer:

i guess the answer is 1.764

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IceJOKER [234]
Yes I can what is it
8 0
3 years ago
How do you get 1.8 from<img src="https://tex.z-dn.net/?f=f%282%29%3D%5Cfrac%7B2%7D%7B1%2Be%5E%7B-%282%29%7D%20%7D" id="TexFormul
Nataliya [291]

Answer:

see explanation

Step-by-step explanation:

\frac{2}{1+e^{-2} } ← evaluate e^{-2} using calculator

= \frac{2}{1+0.135}

= \frac{2}{1.135}

= 1.762.....

≈ 1.8 ( to 1 dec. place )

4 0
2 years ago
Guys the answer guys plz​
ryzh [129]

Answer:

No

Step-by-step explanation:

The definition of a prime number is a number that only has factors of 1 and itself.  So there are only 2 factors.  

4 has 3 factors: 1, 2, and 4.  It has factors of 1 and itself (4), but also has an extra factor (2), so 4 is not a prime number

8 0
3 years ago
Read 2 more answers
Becca sells bracelets for $9 each. She has to pay $4.35 for the materials for each bracelet. How much money does she make from e
damaskus [11]

Answer:

She makes $4.66

Step-by-step explanation:

In this problem we are required to calculate the profit she makes from each bracelet

Given data

Selling price for a bracelet =$9

Cost price for a bracelet = $4.35

Profit= selling price- cost price

Profit = 9-4.35= $4.66

5 0
3 years ago
If events X and Y are independent, what must be true? Check all that apply. P(Y | X) = 0 P(X | Y) = 0 P(Y | X) = P(Y) P(Y | X) =
lana [24]

if events X and Y are independent, then for intersection we multiply the probability

P(Y∩X)  = P(Y) * P(X)

We know that

P(Y|X) =\frac{P(YintersectionX)}{P(X)}

Now we replace P(Y) * P(X) for  P(Y∩X)

P(Y|X) =\frac{P(Y)*P(X)}{P(X)}

Cancel out P(X)

So P(Y|X) = P(Y)

Like that

P(X|Y) =\frac{P(XintersectionY)}{P(Y)}

Now we replace P(X) * P(Y) for  P(X∩Y)

P(X|Y) =\frac{P(X)*P(Y)}{P(Y)}

Cancel out P(Y)

So P(X|Y) = P(X)

P(Y | X) = P(Y)  and P(X | Y) = P(X)  are true



3 0
3 years ago
Read 2 more answers
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