Question

Which is the equation in slope-intercept form for the line that passes through (3, 7)

Answer 1

Answer:

$y = - \frac{5}{3} x + 12$

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

m is the gradient while c is the y-intercept.

3x-5y=8

5y= 3x -8

$y = \frac{3}{5} x - \frac{8}{5}$

Thus, the gradient of the given equation is ⅗.

The product of the gradients of perpendicular lines is -1.

(gradient of line)(⅗) = -1

gradient of line= -1 ÷⅗

gradient of line= $- \frac{5}{3}$

$y = - \frac{5}{3} x + c$

To find the value of c, substitute a coordinate.

When x=3, y=7,

$7 = - \frac{5}{3} (3) + c$

7= -5 +c

c= 7+5

c= 12

Hence, the equation of the line is $y = - \frac{5}{3} x + 12$.