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3 years ago

Find the slope of the line. ( -4, -4), ( 4, 3)

Mathematics

2 answers:

Archy [21]3 years ago

7 0

Answer:

Step-by-step explanation:

kolezko [41]3 years ago

6 0

Answer:

Slope:-1/8

Step-by-step explanation:

Slope=(y2-y1)/(x2-x1)

(-4,4) (4,3)

x1 y1 x2 y2

(3-4)/(4-(-4))

-1/(4+4)

-1/8

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Which of these numbers is not rational?

leva [86]

Answer: A: $\sqrt{3}$

Step-by-step explanation:

The square root of 3 is an irrational number. It is also known as Theodorus' constant, after Theodorus of Cyrene, who proved its irrationality.

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3 years ago

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4 years ago

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Points F,G, and H are collinear such that FG:FH=2/3.If a directed line segment begins at F(-3,2) and ends at H (-3,7), find the

Nana76 [90]

We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
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For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
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Therefore the coordinates of G are (1, 16/3).

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4 years ago

Please help asap.<br> no fake answers or links.<br> picture below.

sesenic [268]

Answer:

b is the correct answer. I'm sure ♡

Step-by-step explanation:

- don't mind this I had to edit my answer lol. but I hope I helped u good luck. If I'm wrong someone can correct me below ☆

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3 years ago

Please help differentiate this!!!!!!!!!

vlada-n [284]

$\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t$

$\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3 \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}$

5 0

3 years ago

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