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Lapatulllka [165]
3 years ago
10

Suppose you graph the points (time, distance) and your friend graphs (distance, time) . How will your graphs be different

Mathematics
1 answer:
Aliun [14]3 years ago
6 0
It depends on what the I.V and D.V are. If the I.V is the distance then I should have been on X. And if the D.V is time then it should have been on the y axis. I.V are something u change, so in this case u r driving the car. And the D.V is the time. Cause u can't change the time and it change on how far u went
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Prove the triangles are congruent
frozen [14]

Answer:

1: two sides and angle of one triangle are congruent.

Step-by-step explanation:

The triangles are congruent because two sides and the generated angle of a triangle correspond to their respective sections. If two angles and the side used in one triangle are identical.

Hope this helps

4 0
3 years ago
Point A is at (3, 2.5) and point B is at (3, 1.4) on a coordinate grid. The distance between the two points is ____. Input numbe
andriy [413]
The points have the same x-coordinate, so they lie on a horizontal line. The distance between them is the difference between their y-coordinates.

2.5 - 1.4 = 1.1

The distance between the two points is 1.1
5 0
3 years ago
What's the difference between 6z and z6
Airida [17]
Simple..

there is a major difference between 6z and z^{6}

6z means: 6 times z

and

z^{6} means: z to the power of 6(z*z*z*z*z*z)

An example...

make z=2...plug n chug..

6z----> 6(2)=12
and
z^{6}--->2^{6}=64

As you can see..there is a major difference.

Thus, your answer.
4 0
3 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
Solve for x and y: 7y−5x=31 & x=4−2y
horrorfan [7]
7*y - 5*(4-2y) = 7y - 20 +10y = 17y-20 = 31,

y =3, x = -2.

Weird 20 min without answer!
7 0
3 years ago
Read 2 more answers
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