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Hunter-Best [27]
3 years ago
14

Factor x^2+ 5x + 6 pleaseee

Mathematics
2 answers:
alekssr [168]3 years ago
6 0

Answer:

( x + 2 ) ( x  +3 )

igomit [66]3 years ago
6 0
( x + 2 ) ( x + 3 ) This is because 2+3=5 and 2x3=6. Plus, x•x= x^2
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Jen rode her bike 1/5 of a mile to her friend's house. It took her 5 minutes to get there. What was Jen's speed?
Molodets [167]

Answer:

1/25 miles per minute

Step-by-step explanation:

Speed is distance divided by time

1/5 miles ÷ 5 minutes

Copy dot flip

1/5 * 1/5

1/25 miles per minute

5 0
3 years ago
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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 23 in. by 13 in. by
faltersainse [42]

Answer:

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is 361.19 in^3.

Step-by-step explanation:

Given that the dimensions of a cardboard is 23 in by 13 in.

Let the side of the square be x in.

Then the length of the box= (23-2x) in

and the width of the box =(13-2x) in

and height = x in.

The volume of the box is = length ×width × height

                                         =[(23-2x)(13-2x)x] in^3

                                         =(299x-72x² +4x^3) in^3

∴V=299x-72x² +4x³

Differentiating with respect x

V'= 299-144x+12x²

Again differentiating with respect x

V''= -144+24x

To find the dimensions, we set V'=0

∴299-144x+12x²=0

Applying Sridharacharya formula that is the solution of a quadratic equation ax²+bx+c is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here a=12, b=-144 , c=299

\therefore x=\frac{-(-144)\pm\sqrt{(-144)^2-4.12.299}}{2.12}

\Rightarrow x= 9.33, 2.67

If  we take x=9.33 in, then the width of the box [13-(2×9.33)] will negative.

∴x = 2.67 in

If at x = 2.67, V''<0 , then the volume of the box will be maximum or V''>0 then volume of the box will be minimum.

V''|_{x=2.67}=-144+(24\times 2.67)=-79.92

Therefore  at x = 2.67, the volume of the box maximum.

The length of the box =[23-(2×2.67)] in

                                    =17.66 in

The width of the box =[13-(2×2.67)] in

                                  =7.66 in

The height of the box= 2.67 in

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is =(17.66×7.66×2.67) in^3

                                                            =361.19 in^3

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3 years ago
In the era just prior to the Reformation, which of the following is true about the Catholic Church?
vovikov84 [41]
The answer is That it had a peaceful relationship with the protestants
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pls help Isabella is saving up money to buy a car. Isabella puts $7,000.00 into an account which earns 3% interest, compounded m
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Answer:

$1,050

Step-by-step explanation:

√Verified.

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