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Sidana [21]
3 years ago
13

When QS=6x and CS=5x-8, what is AB?

Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

AB = x+ 8

Step-by-step explanation:

Given : QS=6x and CS=5x-8

From the given figure,

QS = QC + CS

We are given with  QS  and CS

Replace it the above equation

6x = QC + 5x -8

Solve for QC

Subtract 5x on both sides

x = QC + -8

Add 8 on both sodes

QC= x + 8

QABC is a rectangle

QC = AB

So AB = x+ 8


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After *triangle* ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?
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<h3>Answer:  4 square inches</h3>

Explanation:

Square the linear scale factor to get 5^2 = 25

This means that,

new area = 25*(old area)

We take this idea in reverse to find the old area

old area = (new area)/25

old area = (100 sq inches)/25

old area = 4 square inches

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-4.41666666667



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Evaluate the following expression 2+(3-2×2)×1
neonofarm [45]
2•3=9 2•2=4 2•2=4 9+4+4=17 the answer is 17
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3 years ago
Sean tried to drink a slushy as fast as he could. He drank 5 milliliters of slushy each second and finished all
castortr0y [4]

Answer:

graph like this:

Step-by-step explanation:

First, in 5 seconds, we know that he drinks 25 mL of slushy. We know this because 1 second is 5 mL, so 5 seconds is 25 mL. So, your graph should be going from the 5 second to 25 mL mark, then the 10 second and 50 mL mark, then the 15 mL and 75 mL mark, and so on.

6 0
2 years ago
A movie theater has a 24​-foot-high screen located 6 feet above your eye level. If you sit x feet back from the​ screen, your vi
pantera1 [17]

Answer:

The viewing angles are as follows:

For x=5 feet, θ = 0.529 radians

For x=10 feet, θ = 0.708 radians

For x=15 feet, θ = 0.726 radians

For x=20 feet, θ = 0.691 radians

For x=25 feet, θ = 0.640 radians

Step-by-step explanation:

The viewing angle is given as:

θ = tan⁻¹(30/x) - tan⁻¹ (6/x)

where x is the distance between you and the screen.

The question is asking us to find the viewing angle θ at various distances. The distance value needs to be substituted in the above equation in place of x. So,

<u>For x=5 feet:</u>

θ = tan⁻¹(30/5) - tan⁻¹ (6/5)

  = 1.4056 - 0.8761

θ = 0.529 radians

<u>For x = 10 feet:</u>

θ = tan⁻¹(30/10) - tan⁻¹ (6/10)

  = 1.249 - 0.540

θ = 0.708 radians

<u>For x = 15 feet:</u>

θ = tan⁻¹(30/15) - tan⁻¹ (6/15)

  = 1.107 - 0.380

θ = 0.726 radians

<u>For x = 20 feet:</u>

θ = tan⁻¹(30/20) - tan⁻¹ (6/20)

  = 0.983 - 0.291

θ = 0.691 radians

<u>For x = 25 feet:</u>

θ = tan⁻¹(30/25) - tan⁻¹ (6/25)

  = 0.876 - 0.235

θ = 0.640 radians

5 0
2 years ago
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