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artcher [175]
3 years ago
8

Imagine that a tank is filled with water. The height of the liquid column is 7 meters and the area is 1.5 square meters (m2). Wh

at's the force of gravity acting on the column of water?
Physics
2 answers:
Korolek [52]3 years ago
4 0

Answer: 1.03 × 10⁵ N

Explanation:

Force of gravity due to liquid column in a tank is given by the product of pressure due to the liquid column and area on which this pressure is acting.

Force, F = P × A

Pressure, P = ρ g h

where, ρ is the density of the liquid

g is the acceleration due to gravity

h is the height of the liquid column

It is given that, h = 7 m

Area, A = 1.5 m²

g = 9.81 m/s²

density of water, ρ = 1000 kg/m³

⇒ F =  ρ g h × A = 1000 kg/m³ × 9.81 m/s² × 7 m × 1.5 m² = 103005 N

Hence, force of gravity acting on the column of water is 1.03 × 10⁵ N

Marta_Voda [28]3 years ago
3 0
The answer to your question is 102,900N
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A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t
salantis [7]

Answer:

2.07

Explanation:

Since you didn't supply the drawing, here is what I assumed:

A is the corner opposite the axis of rotation

B is one of the remaining two corners

L1 is the side between A & B

Centripetal acceleration is given by:

ac = v^2 / r = (v / r) * (v / r) * r…………1

Also angular speed is

w = v / r,………….2

Substituting (2) in (1) gives:

ac = (v / r) * (v / r) * r……….3

= (v / r)^2 * r

= w^2 * r

Therefore, the angular acceleration at A and at B are given by:

acA = w^2 * rA……..4

acB = w^2 * rB……..5

It is given that:

acA = n * acB…………6

Substituting (4) and (5) into (6) gives:

w^2 * rA = n * w^2 * rB ……….7==>

rA = n * rB……..8

In terms of the sides L1 and L2:

rA = sqrt (L1^2 + L2^2)…….9

and

rB = L2…………10

Considering (8):

n * L2 = sqrt (L1^2 + L2^2)………11

Squaring both sides:

n^2 * L2^2 = L1^2 + L2^2……….12

Dividing by L2^2:

n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13

= (L1 / L2)^2 + 1 ==>

n^2 - 1 = (L1 / L2)^2 ………14==>

L1 / L2 = sqrt (n^2 - 1) ………15

= sqrt (2.30^2 - 1)

= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30

8 0
2 years ago
A child sits on the edge of a spinning merry go round that has a radius of 1.5 . The child’s speed is a 2m/s. What is the child’
Leto [7]

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Explanation:

Centripetal acceleration is defined as v^2/r; in this case, it's 2^2/1.5, which is 2.67.

3 0
2 years ago
A trained eye in the dark for an extended period of time may pick up a light stimulus from a light source, at the lowest radiate
frez [133]

Answer:

    #_photons = 30 photons / s

Explanation:

Let's start by finding the energy of a photon of light, let's use the Planck relation

         E = h f

the speed of light is related to wavelength and frequency

         c = λ f

we substitute

         E = h c /λ

         E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹

         E₀ = 3.978 10⁻¹⁹ J

now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second

          #_photons = 1 photon   (E / Eo)

          #_photons = 1  1.2 10⁻¹⁷ /3.978 10⁻¹⁹

          #_photons = 3.0 10¹

          #_photons = 30 photons / s

3 0
2 years ago
the amount of time for one particle of the medium to make one comlpete vibration cycle is a good description of
-Dominant- [34]
That's the definition of the PERIOD of the vibration.
It's exactly the reciprocal of the vibration's frequency.
7 0
2 years ago
Read 2 more answers
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Serjik [45]
The elastic potential energy of a spring is given by
U= \frac{1}{2}kx^2
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The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
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In our problem, initially the spring is uncompressed, so x_i=0. Therefore, the work done by the spring when it is compressed until x_f is
W=- \frac{1}{2}kx_f^2
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
8 0
3 years ago
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