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3 years ago

The cloud of interstellar dust and gas that forms a star is known as a

2 answers:

8 0

The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.

aliina [53]3 years ago

4 0

Correct answer choice for question 1 is:

D) Nebula.

Explanation:

A nebula is an interstellar cloud of dust, hydrogen, helium and other ionized vapors. Basically, the nebula was a sign for any distributed enormous object, including galaxies behind the Milky Way. Most nebulae are of a large size, some are numbers of light years in diameter. A nebula that is almost visible to the human eye from Earth would appear larger, but no flashing, from close by. The Orion Nebula, the glowing nebula in the sky that controls a region twice the diameter of the full Moon, can be observed with the naked eye but was dropped by early scientists.

Correct answer choice for question 2 is :

D) Venus

Explanation:

Venus is the second planet from the Sun, revolving it every 224.7 Earth days. It has the largest revolution time of any planet in the Solar System and turns in the different direction to most other planets. It does not have any real satellites. It is the second glowing natural object in the night sky after the Moon, leading an obvious magnitude of 4.6 bright quite to throw shadows at night and, unusually, obvious to the naked eye in full daylight.

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What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A

MrRa [10]

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

$P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA$

8 0

2 years ago

Two separate masses on two separate springs undergo simple harmonic motion indefinitely (the surface is frictionless). In CASE 1

Artemon [7]

Answer:

$\frac{F_1}{F_2} =\frac{1}{2}$

Explanation:

Assuming the we have to find ratio maximum forces on the mass in each case

we know that in a spring mass system

F= Kx

K= spring constant

x= spring displacement

Case 1:

$F_1=2k\times d$

case 2:

$F_2=2k\times 2d$

therefore, $\frac{F_1}{F_2} = \frac{2K\times d}{2K\times 2d}$

$\frac{F_1}{F_2} =\frac{1}{2}$

4 0

3 years ago

By newton third law of motion, we know that if a rocket ship pushes down on the ground, the ground will push back up on the rock

Furkat [3]

We don't know that at all. The 3rd law says that the REaction is opposite and EQUAL to the action. We don't know where that "twice as much" comes from.

6 0

3 years ago

Read 2 more answers

Your friend's 10.8 g graduation tassel hangs on a string from his rearview mirror. When he accelerates from a stoplight, the tas

Nitella [24]

The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N
Ф = 34.4 °

<h3>What is the tension in the string holding the tassel. ?</h3>

Generally, the equation for Tension is mathematically given as

$TCos\theta = mg$

Therefore

$TCos6.58^{o} = 19.8*10^{-3}*9.8$

T = 0.1953 N

b).

Where

$T* sin \theta = ma$

$0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a$

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

$sin\theta = \frac{a}{2}$

$\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}$

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

Read more about tension

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4 0

2 years ago

A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut

Afina-wow [57]

The weight of the shuttle is $6.94\cdot 10^6 N$

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

$W=mg$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

$m=7.08\cdot 10^5 kg$

So, its weight is

$W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N$

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

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6 0

3 years ago