33 + 12 would be 45 centimeters square
Hey there :)
Now lets name each house
A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft
Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft
at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft
at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft
Do the same for D , E and F
at D
= 6000 ft
at E
= 7000 ft
at F
= 15000 ft
You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.
Answer:
<h3>6 inches</h3>
Step-by-step explanation:
If Casey and Stephanie order a rectangular cake of dimension 24in by 18in, to get the side length of the largest piece of square, we will find the greatest common factor of both dimension as shown:
24 = 2 * 2 * (2 * 3)
24 = (2 * 3) * 4
24 = 6*4
18 = (2*3)*3
18 = 6*3
From both factors you an see that the common GCF is 6. This shows that the length of the largest square pieces into which Casey and Stephanie can cut the cake is 6 inches.
So you subtract $22.89 from $54.73 to get a total of $31.84 and that’s how much the customer paid.
Answer:
9x^2-3x+4
Step-by-step explanation:
(3x^2+2x^2-5x+7)+(4x^2+2x-3)
5x^2-5x+7+4x^2+2x-3
5x^2+4x^2-5x+2x+7-3
9x^2-3x+7-3
9x^2-3x+4
