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ELEN [110]
3 years ago
14

if a point on the graph of a proportional relationship is located at 3,4, can you determine the constant of proportionality? exp

lain
Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

The answer is: No, because we also need to know the type of proportionality


In mathematics, we talk about proportionality when two variables are related and this relationship is that there is a constant ratio between them. There are two types of proportionality.


1. Direct Proportionality:

If there are two variables x and y, we can write the relationship between them as follows:


y=kx


So, by substituting the point in this equation we have that the constant of proportionality is:


4=k(3) \\ \\ \therefore \boxed{k=\frac{4}{3}}


2. Inverse Proportionality:


In this case, the relationship is:


y=\frac{k}{x}


So, the constant of proportionality is:


4=\frac{k}{3} \\ \\ \therefore \boxed{k=12}


As you can see, we have found two different values of the constant of proportionality. So, it is necessary to know the type of proportionality.

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3 years ago
2 to the power of 4 x 2 to the power of 9 x 2
attashe74 [19]

Answer: 8^2 18^2

Step-by-step explanation: The way that you figure out the power is by multiplying the 4x2=8 than the 9x2=18 than you raise them both to the second power.

6 0
3 years ago
Can someone please explain this to me? Thanks!
Makovka662 [10]

Answer:  Choice D

\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\

==========================================================

Explanation:

Let g(t) be the antiderivative of g'(t) = \sqrt{1+t^3}. We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\

From here, we apply the derivative with respect to x to both sides. Note that the g(\pi) portion is a constant, so g'(\pi) = 0

\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\

\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\

Answer is choice D

5 0
2 years ago
Read 2 more answers
Please help and thank you
artcher [175]

The answer is (2,3). If you plot each answer choice you'll see that (2,3) is the only one that is within the shaded area, which means that it satisfies the given system of innequalities.

5 0
3 years ago
Organize the following polynomial expressions from least to greatest based on their degree:
Mumz [18]

Answer:

Step-by-step explanation:

We have to organize the given polynomials from the least to greatest based on their degrees.

A). x + 2xyz

Here xyz = x^{1}y^{1}z^{1}

Power of x is = 1

Power of y = 1

and power of z = 1

So degree of (x + xyz) will be degree of the highest degree term = 1 + 1 + 1 = 3

B). 9x³y²

Degree of this term = power of x + power of y = 3 + 2 = 5

C). 18x²+ 5ab - 6y

Degree of the polynomial = Highest degree of the variable x = 2

D). 4x^{4}+3x^{2}-x-4

Degree of highest degree term 4x^{4} = 4

So sequence of the polynomials based on their degrees will be

C - A - D - B [From lowest to highest]

8 0
3 years ago
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